Question

pls solve its urgent​

Answer 1

$\displaystyle\boxed{\bold{(a+b)^3=a^3+b^3+3ab(a+b)}}\\\\\\\\\text{Given}\:\:\mathrm{x=2^{\frac{1}{3}}+2^{\frac{2}{3}}}\\\\\text{cubing both sides}\\\\\\x^3=\big(2^{\frac{1}{3}}+2^{\frac{2}{3}}\big)^3\\\\x^3=(2^{\frac{1}{3}})^3+(2^{\frac{2}{3}})^3+\big[3\times2^{\frac{1}{3}}\times2^{\frac{2}{3}}(2^{\frac{1}{3}}+2^{\frac{2}{3}})\big]\\\\x^3=2^{\frac{1}{\not3}\times\not3}+2^{\frac{2}{\not3}\times\not3}+\big[3\times2^{(\frac{1}{3}+\frac{2}{3})}\times(2^{\frac{1}{3}}+2^{\frac{2}{3}})\big]\\\\x^3=2+2^2+3\times2\big[2^{\frac{1}{3}}+2^{\frac{2}{3}}\big]\\\\x^3=6+6x\\\\\underline{x^3-6x=6}$