Math, asked by Anonymous, 9 months ago

pls solve its urgent

abe nhi ata to mat do pls class bilkul mat puchna​

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Answered by Ҡαηнα
17

HEY DUDE

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Answered by bhanuprakashreddy23
10

Answer:

Resistances in series add up.

RT = R1 + R2 + R3

RT = 20 Ω + 30 Ω + 50 Ω

RT = 100 Ω

Total current is determined by the voltage of the power supply and the equivalent resistance of the circuit.

IT = VT/RT

IT = 125 V/100 Ω

IT = 1.25 A

Current is constant through resistors in series.

IT = I1 = I2 = I3 = 1.25 A

The voltage drops can be found using Ohm's law.

V1 = I1R1

V1 = (1.25 A)(20 Ω)

V1 = 25.0 V

V2 = I2R2

V2 = (1.25 A)(30 Ω)

V2 = 37.5 V

V3 = I3R3

V3 = (1.25 A)(50 Ω)

V3 = 62.5 V

Verify your calculations by adding the voltage drops. On a series circuit they should equal the voltage increase of the power supply.

VT = V1 + V2 + V3

125 V = 25.0 V + 37.5 V + 62.5 V

125 V = 125 V

We're good, so let's finish.

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