pls solve me the answer ill make u brainlist
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Step-by-step explanation:
Given: ∠RTP=∠QSP=90°
(i)ΔQSR ≅ ΔRTQ :
In ΔQSR and ΔRTQ
QR is common
∠QSR =∠RTQ=90°
QS = RT ((given))
∴By RHS criterion, ΔQSR ≅ ΔRTQ
(ii)
By CPCT of (i) , ∠SQR=∠TRQ
Since ∠PQR=∠SQR, and ∠PRQ=∠TRQ
∠PQR=∠PRQ
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