Math, asked by anandrajo1, 11 months ago

pls solve no ii ..

pls pls pls ​

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Anonymous: ___k off

Answers

Answered by siddhartharao77
3

Answer:

2/3

Step-by-step explanation:

Given polynomial is f(x) = x² - 2x + 3.

Here a = 1, b = -2, c = 3.

α,β are the roots of the polynomial.

Sum of roots:

α + β = -b/a

⇒ α + β = -(-2)/1

⇒ α + β = 2

Product of roots:

αβ = c/a

⇒ αβ = 3/1

⇒ αβ = 3

Now,

(ii)

Given: (α - 1/α + 1) + (β - 1/β + 1)

= [(α - 1)(β + 1) + (β - 1)(α + 1)]/(α + 1)(β + 1)

= [(αβ + α - β - 1 + αβ + β - α - 1)]/[(αβ + α + β + 1)]

= [(2αβ - 2)]/[3 + 2 + 1]

= 4/6

= 2/3

Hope it helps!


anandrajo1: no wrong method
anandrajo1: this is not ans
siddhartharao77: What is the answer?
anandrajo1: k ( x*2 - 2/3x +1/4 )
siddhartharao77: In the question it was not asked to find the equation of quadratic polynomial. It was asked to find the value of (ii)
anandrajo1: no find the quadratic poly. is ask in que .
siddhartharao77: No.. please read the question carefully
Answered by atulrajcool
0
see the images

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