Pls solve Q 21 !!!!!!
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candy10:
which class are you studying in
9th standard
oh
I am also studying in 9 standard
if u know this question
then pls solve ghis
this*
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CF=1/2AC
by converse of mid point theorem , Q is the mid point of AC
so AQ=QC=CF
in triangle DQF , C is the mid point of Qf and PC//DQ
so by converse of mid point theorem
DP=PF
in triangle EBD and DPC
angle EDB = angle CDP
angle E= angle P
BD=DC
by AAS congrence criterion
triangle EBD is congruent to triangle DPC
so ED=DP
ED=DP=PF
ED+DP+PF=EF
3ED=EF
ED=1/3EF answer
by converse of mid point theorem , Q is the mid point of AC
so AQ=QC=CF
in triangle DQF , C is the mid point of Qf and PC//DQ
so by converse of mid point theorem
DP=PF
in triangle EBD and DPC
angle EDB = angle CDP
angle E= angle P
BD=DC
by AAS congrence criterion
triangle EBD is congruent to triangle DPC
so ED=DP
ED=DP=PF
ED+DP+PF=EF
3ED=EF
ED=1/3EF answer
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