pls solve Q's no 2. advance thank u
Answers
Answer:
QUESTION:
A man walks on a straight road from his home to a market 2.5 km away with a speed 5 km/h. find the market closed he instantly comes and walk back home speed 7.5 km/h. The average speed of the man of the in interval of time 0 to 50 min is equal to
ANSWER:
6 km/h
Step by step explanation:
Given that,
A man walks on a straight road from his home to a market 2.5 km away with a speed 5 km/h.
here,
we have,
distance between market and his house = 2.5 km
total distance travelled = 2 × 2.5
= 5 km
given time for finding average speed
= 0 - 50 minutes
= 50 minutes
= 50/60 hour
= 5/6 hour
Average speed
total distance travelled/total time taken
= 5/(5/6)
= 30/5
= 6 km/h
so,.
Average speed from 0 - 50 minutes
= 6km/h
his speed of going market = 5 km/h
so,
here,
time taken to reach market
= 2.5/5
= 0.5 h
now,
while
coming back his speed = 7.5 km/h
so,
here time taken to returning home =
2.5/7.5
= 1/3 h
now,
Average speed =
total distance travelled /total time taken
total distance travelled = 2 × 2.5
= 5 km [because he came back]
total time taken = 1/3 + 1/2
= 5/6
Average speed = 5/(5/6)
5 × 6/5
= 6 km /h
so,
average velocity in the whole journey =