Question

Pls solve Q10..pls help..N I'll surely mark you as BRAINLIEST!!!!!!

Answer 1

you can see that line which i had cut that is only i can prove
the answer i have been doing after that line is cut(HOPE IT HELPS U)

Answer 2

Hello boy !

according to your question x = > { ( √2a+3b ) + ( √2a-3b ) } / { ( √2a+3b ) - ( √2a-3b ) }  now the only method i to rationalize it and solve the question because without rationalizing it may creates some problem while answering :-) but better is to apply componendo and dividendo rule for easy calculations

========================================================        x /1 = > { ( √2a+3b ) + ( √2a-3b ) } / { ( √2a+3b ) - ( √2a-3b ) }

first thing i want to tell you what is componendo and dividendo rule

Componendo et Dividendo is a theorem on proportions that allows for a quick

way to perform calculations and reduce the amount of expansions needed.

as a/b = >    (a+b)/(a-b)  =>   ( a+bk ) /( a-bk)

by componendo and dividendo 

(x+1) /(x-1) = > { { ( √2a+3b ) + ( √2a-3b ) } + { ( √2a+3b ) - ( √2a-3b ) } } / { ( √2a+3b ) - ( √2a-3b ) } - { ( √2a+3b ) + ( √2a-3b ) } }

NOW AFTER SOLVING THIS WE GOT :=)

(x+1) /(x-1) = > 2 (√2a+3b) / 2 ( √2a-3b )

(x+1) /(x-1)  => (√2a+3b) / ( √2a-3b )

NOW SQUARING BOTH SIDES TO REMOVE ROOTS  :-)

{(x+1) /(x-1)}² = > (2a+3b) / ( 2a-3b )

{ x ² + 2x + 1 } / {x ²- 2x + 1} => (2a+3b) / ( 2a-3b )

BY APPLYING COMPONENDO DIVIDENDO RULE AGAIN WE GOT

 {{ x ² + 2x + 1 } +{x ²- 2x + 1} }/{ {x ²- 2x + 1} -{ x ² + 2x + 1 }}   =>  /{ (2a+3b)  + ( 2a-3b )  } / {( 2a-3b ) - (2a+3b)  }

now after solving it we got  :=)

{ x  ² +1 } / 2x  = > 2a /3b

so  3bx ² +3b = > 2ax

3bx ² +3b -2ax => 0  HENCE PROVE

HOPE THIS HELPS YOU

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@ engineer gopal iit roorkey b=tech

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