Math, asked by rajib16, 1 year ago

pls solve question no 10

Attachments:

neosingh: which class
neosingh: it is similar to q 9 , were u able to do that
rajib16: class 8
rajib16: pls help me sir

Answers

Answered by neosingh
1
Please find your answer
Attachments:

rajib16: tq sir
Answered by mriganka2
0
x = \frac{1}{5 - x}
 = > \frac{1}{x} = 5 - x
 = > x + \frac{1}{x} = 5
so \: now
 {x}^{3} + \frac{1}{ {x}^{3} }
 = {(x + \frac{1}{x}) }^{3} - 3 \times x \times \frac{1}{x} \times (x + \frac{1}{x} )
 = {5}^{3} - 3 \times 5
 = 125 - 15
 = 110

please mark this answer brainliest.
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