Question

Pls solve question number 2

Answer 1

HEY MATE!

HERE IS YOUR ANSWER:

Let the two consecutive numbers be x and x-1

Now, we are given that

x^2-(x-1)^2=31

x^2-[x^2+1-2x]=31

x^2-x^2-1+2x=31

-1+2x=31

2x=31+1

2x=32.

x=16

NUMBERS ARE 16 AND 15.

HOPE IT HELPED ^_^

Answer 2

Step-by-step explanation:

Let two consecutive number is x and x+1.

=> (x+1)² - x² =31

=> x² + 2x +1 - x² = 31

=> 2x = 30

=> x = 15

The consecutive number is 15 and 16.