Pls solve sir ji this question
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AB || CD , so 65° = x + 20° as 65° and ( x + 20 )° are alternate angles.
65° = ( x + 20 )°
65° - 20° = x
45° = x
x + 20° = 45 + 20° = 65°
Angle which is a linear pair of x is equal to y as EF || CD and y and that angle are alternate angles.
180° - x° = y
180° - 45° = y
135° = y
Therefore, x = 45° and y = 135°
Abhishek777:
y and x are supplementary
or y+x = 180°
Angle which is a linear pair of x + 20 is equal to y as it is alternate angle to y
coz they are interior angles on the same side of the transversal
HOW ?
these two angles lie on two different transversals
wait
hmm
done :-)
^_^
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the solution is in the attachment as I had done it in paper
and
Name the points where the transversal intersects AF as G, BE as H and CD as I
And the point on which y lies as O
Hope this helps please mark me as brainliest thnx
*This will be the solution only if the lines AB||BE and BE||CD
and
Name the points where the transversal intersects AF as G, BE as H and CD as I
And the point on which y lies as O
Hope this helps please mark me as brainliest thnx
*This will be the solution only if the lines AB||BE and BE||CD
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and see the naming of the points may differ from ur diagram so plz check from my diagram which is drawn on the paper
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