pls solve the above question...
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here is ur answer....
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sree999:
thanks a lot
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(65^-2)^1/4 - (36^-2)^1/4
{we have (a^m)^n = a^(mn)}
[(65)^(-1/2)] - [(36)^(-1/2)]
= [√(65^(-1)] - [√36^(-1)]
{°•° a^(1/2) = √a}
= (1/√65) -(1/√36) ----------(1)
{°•° a^(-1)= 1/a}
√36= √(6²) = (6²)^(1/2)= 6
Now find √65
65 is a non perfect square.
64<65<81 [here 64 and 81 are perfect squares]
8²<65<9²
=> 8<√65<9
√65= 8 + (1/(2*8))= 8 + (1/16)= 8 + 0.0625
= 8.0625
substitute in (1)
=>(1/8.0625) - (1/6)
=>(6 - 8.0625)/(6*8.0625)
=>-2.0625/48.375
=>-(11/258)
=>-0.04263
The Value of what you've just asked is -0.04263
{::: If you didn't get the way I have calculated square root of non perfect square, comment or see my answer in my profile}
;)
hope it helps
mark brainliest if you find this helpful..
{we have (a^m)^n = a^(mn)}
[(65)^(-1/2)] - [(36)^(-1/2)]
= [√(65^(-1)] - [√36^(-1)]
{°•° a^(1/2) = √a}
= (1/√65) -(1/√36) ----------(1)
{°•° a^(-1)= 1/a}
√36= √(6²) = (6²)^(1/2)= 6
Now find √65
65 is a non perfect square.
64<65<81 [here 64 and 81 are perfect squares]
8²<65<9²
=> 8<√65<9
√65= 8 + (1/(2*8))= 8 + (1/16)= 8 + 0.0625
= 8.0625
substitute in (1)
=>(1/8.0625) - (1/6)
=>(6 - 8.0625)/(6*8.0625)
=>-2.0625/48.375
=>-(11/258)
=>-0.04263
The Value of what you've just asked is -0.04263
{::: If you didn't get the way I have calculated square root of non perfect square, comment or see my answer in my profile}
;)
hope it helps
mark brainliest if you find this helpful..
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