Math, asked by akshita8928, 5 months ago

pls solve the problem it's urgent.

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Answered by faisalraisinsm

0

Answer:

L. H. S 1+sectheta/sectheta

=1+1/costheta/1/costheta

=costheta+1/costheta/1/costheta

=1+costheta

R. H. S

sin^2theta/1-costheta

=1-cos^2theta/1-costheta

=(1-costheta)*(1+costheta)/(1-costheta)

=(1+costheta)

L. H. S=R.H.S

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