Question

pls solve the problem. wrong answer will be reported​

Answer 1

$Let \: radius \: of \: a\: hemispherical \: bowl = r \: cm$

$Area \: of \:the \:sheet \: required \: to \:make \\the \: bowl = 173.25 \:cm^{2}$

$\implies 2\pi r^{2} = 173.25$

$\implies 2 \times \frac{22}{7} \times r^{2} = 173.25$

$\implies r^{2} = \frac{173.25 \times 7}{2 \times 22 }$

$\implies r^{2} = \frac{1212.74}{44}$

$\implies r^{2} = 27.5625$

$\implies r = 5.25 \:cm$

$\red { Diameter \:of \:the \:bowl } = 2r \\= 2 \times 5.25 \\= 10.5 \:cm$

Therefore.,

$\red { Diameter \:of \:the \:bowl } \green {= 10.5 \:cm}$

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