Question

(pls solve the question correctly and with explanation urgently, pls) FIND THE AREA OF TRIANGLE PQR AND HEIGHT PS, GIVEN SIDES ARE TR=15 cm,QR=20cm and QT =12cm.

Answer 1

Area= sqrt(s(s-a)(s-b)(s-c))
Where a=12, b=15,c=20
And s=(a+b+c)/2 =(12+15+20)/2 =47/2=23.5
Area=sqrt(23.5(23.5-12)(23.5-15)(23.5-20))
= sqrt(23.5*11.5*8.5*3.5)
=sqrt(8039.9375)
=89.6656986 sq cm
NOT ENOUGH INFORMATION TO FIND PS