pls solve the question immediately
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Step-by-step explanation:
For any triangle ,
From cosine rule ,
cosA=
2bc
b
2
+c
2
−a
2
acosA=a
2bc
b
2
+c
2
−a
2
cosB=
2ac
a
2
+c
2
−b
2
bcosA=b
2ac
a
2
+c
2
−b
2
⟹b
2ac
a
2
+c
2
−b
2
=a
2bc
b
2
+c
2
−a
2
a
2
b
2
+b
2
c
2
−b
4
=a
2
b
2
+a
2
c
2
−a
4
b
2
c
2
−b
4
−a
2
c
2
+a
4
=0
b
2
(c
2
−b
2
)−a
2
(c
2
−a
2
)=0
a
2
(c
2
−a
2
)=b
2
(c
2
−b
2
)
⟹a=b
b
2
c
2
−a
2
=
a
2
c
2
−b
2
⟹c
2
=a
2
+b
2
So the triangle either must be Isosceles or Right angled please mark as brainllies
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