pls solve the question in the picture (chapter is arithmetic progression)
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In the Two A.P.s let the first terms be x and y redpectively. Given, common diff., d = constant.
Also given,
50th term of first A.P - 50th term of the other A.P. = 50
Then, {x+(50-1)d} - {y+(50-1)d} = 50
x + 49d - y -49d = 50
x - y = 50
x + (80-1)d - y - (80-1)d = 50
{x+(80-1)d} - {y+(80-1)d} = 50
80th term of first AP - 80th term of secon AP = 50
Also given,
50th term of first A.P - 50th term of the other A.P. = 50
Then, {x+(50-1)d} - {y+(50-1)d} = 50
x + 49d - y -49d = 50
x - y = 50
x + (80-1)d - y - (80-1)d = 50
{x+(80-1)d} - {y+(80-1)d} = 50
80th term of first AP - 80th term of secon AP = 50
Revti1:
that was smart work. thanks for the help
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