Question

PLS SOLVE THE QUESTIONS BELOW . I WILL MARK AS BRAINLIEST . THANK YOU

Answer 1

Step-by-step explanation:

$questin \: 1 = \\ 3 {x}^{2} - 2x - 1 \\ where : x = 1 \\ put \: the \: value \: of \: x \\ 3( {1)}^{2} - 2 \times 1 - 1 \\ 3 - 2 - 1 \\ 3 - 3 \\ = 0 \\ value \: of \: x \: is \: zero \: of \: polynomial \\ \\ ii)2 {x}^{2} - 6x + 3 \\ where : x = \frac{1}{2} \\ \\ 2 \times ( \frac{1}{2} ) {}^{2} - 6 \times \frac{1}{2} + 3 \\ \frac{1}{4} - 3 + 3 \\ \frac{1}{4} \\ value \: of \: x \: is \: not \: zero \: of \: polynomial \\ \\ iii) (2x + 3)(3x - 2) \\ where : \: x = \frac{2}{3} \\ (2 \times \frac{2}{3} + 3)(3 \times \frac{2}{3} - 2) \\ (\frac{4 + 9}{3} )(2 - 2) \\ \frac{13}{3} \times 0 \\ 0 \: \\ value \: of \: x \: is \: zero \: of \: polynomial \\ iv) {x}^{2} + x + 1 \\ where : x = - 1 \\ ( - 1) {}^{2} - 1 + 1 \\ 1 - 1 + 1 \\ 1 \\ value \: of \: x \: is \: not \: \: zero \: of \: polynomial \\ v) {x}^{2} + 6x + 5 \\ where : x = - 1 \: and \: x = - 5 \\ a)x = - 1 \\ ( - 1) {}^{2} + 6 \times - 1 + 5 \\ 1 - 6 + 5 \\ 6 - 6 \\ 0 \\ value \: of \: x \: is \: zero \: of \: polynomial \\ b)( - 5) {}^{2} + 6 \times - 5 + 5 \\ 25 - 30 + 5 \\ 30 - 30 \\ 0 \\ value \: of \: x \: is \: zero \: polynomial$

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