Question

pls solve the sum no 62​

Answer 1

Answer:

you have given sum no 63..

Answer 2

don't leave watch it.it is very interesting sum

now we can Write log(a) x

as logx/loga

and

logy*m=mlogy

remember there are n terms don't forget it important

logx/loga+logx*2/loga*2+log*3/loga*3.............logx*n/loga*n

so now

logx/loga+2/2(logx/loga)+.........

n/n(logx/loga

so the equation is

logx/loga+logx/loga+.... ............logx/loga

so there n terms

so as there n terms

logx/loga+logx/loga......... nterms

so we take logx/loga common

logx/loga (1+1+..........1)

as there n terms so the total is

logx/loga(n)

nlog(a)x

hence proved