Question

pls solve this..
chapter: equation of a line​

Answer 1

Answer:

here the explanation plz recheck it .If any problem ask me

Answer 2

Answer:

8

Step-by-step explanation:

Let the coordinates of point of division be (x,y) and the ratio be k:1.

(x,y) = (mx2 + nx1/m+n, my2 + ny1/m+n)

(x,y) = {k(2) + 1(8)/k+1, k(1) + 1(-9)/k+1}

(x,y) = {2k + 8/k+1, k-9/k+1}

x = 2k+8/k+1, y = k-9/k+1

Putting values of x and y in 2x+3y-5=0

2(2k+8/k+1) + 3 (k-9/k+1) -5 =0

4k+16+3k-27/k+1 = 5

7k-11/k+1 = 5

7k-11 = 5k+5

7k-5k = 5+11

2k = 16

k = 8