Question

pls solve this fast​

Answer 1

Answer:

4

Step-by-step explanation:

Given:

$log_{x}( log_{18}( \sqrt{2} + \sqrt{8} ) ) = - \frac{1}{2}$

We know that,

$log_{a}(b) = m = > b = {m}^{a}$

so,

$= > log_{18}( \sqrt{2} + 2 \sqrt{2} ) = {x}^{ - \frac{1}{2} }$

$= > log_{ {(3 \sqrt{2} )}^{2} }(3 \sqrt{2} ) = {x}^{ - \frac{1}{2} }$

We know that,

$log_{ {a}^{n} }(b) = m = > \frac{1}{n} log_{a}(b) = m$

so,

$= > \frac{1}{2} log_{3 \sqrt{2} }(3 \sqrt{2} ) = {x}^{ - \frac{1}{2} }$

$= > \frac{1}{ \sqrt{x} } = \frac{1}{2}$

$= > \sqrt{x} = 2$

$= > x = 4$

Hope this will help yoi....!