pls solve this fast
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All the questions are based on exterior angle concept.
Just keep one thing in mind. No matter how many sides a polygon has, the sum of exterior angles is ALWAYS 360°.
Hence
Q 5)
i) 360°
ii) 360°
iii) 360°
iv) 360°
v) 360°
(note: sum of interior angle is not constant. It depends upon the number of sides and is equal to (n - 2)*180°)
Q 6) given one exterior angle = 20°
no. of sides = 360°/20°
= 18
Q 7). sum of exterior angles = 360°
y + 2y + 3y + 3y + 4y + 5y + 6y = 360°
24y = 360°
y = 360°/24
y = 15°
Answered by
0
Answer:
Q. 5 (I) 360°
(II) 360°
(III) 360°
(IV) 360°
Q. 6 No. of sides = 18
Q. 7 y = 15°
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