Math, asked by vivek512, 1 year ago

pls solve this fast

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Answered by kaira25
1
probability( of getting an event)=no of possible outcomes/total no of events


here total no of events is=(11,12,13,14,15,16,21,22,23,24,25,26,31,32,33,34,35,36,41,42,43,44,45,46,51,52,53,54,55,56,61,62,63,64,65,66)
=36




1) no of possible outcomes=11,12,13,14,15,21,22,23,24,31,32,33,41,42,51)
=15
probability (of getting a sum less than 7 )=15/36
=5/12

2) no of possible outcomes = (11,12,13,14,15,16,21,22,23,24,25,26,31,32,33,34,35,41,42,43,51,52,53,61,62,63)
probaility (of getting a product less tha 16) =26/36
=13/18


3) no of possible outcomes=( 11 ,33,55)
=3
probability (of getting a doublet of odd no)=3/36
=1/12



hope it helps uhhh....if uhh r satisfied thn plzzzz mark a brainliest ans..... thank you
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