Question

Pls solve this i will mark the right answer as brainlist​

Answer 1

In △ABC

∠ADB = ∠ADC [Each equal to 90°] and, ∠EBY = ∠DAC

[Each equal to complement of ∠BAD i.e., 90° - ∠BAD \right]

Therefore, by AA-criterion of similarity, we have

△DBA ~ △DAC

[∠D > ∠D, ∠DBA > ∠DAC and ∠BAD > ∠DCA]

DB/DA= DA/DC

BD/AD=AD/DC

AD² = BD x DC

Answer 2

Answer:

Mark me as brainlist answer