pls solve this maths question no. 31
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r1 is radius of Ist cylinder and r2 is of 2nd cylinder also same h1 and h2
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sidakdeep2016:
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Given :-r=3.4cm
h=5.8
Csa if cone = πrl
l=?
l^2=r^2+h^2
l^2=3.4^2+5.8^2
l^2=11.56+33.64
l^2=45.2
l=√45.2
l=6.7
csa=πrl
=22/7×3.4×6.7
=71.59cm^3
radius of new cone formed=1.7cm
area =71.59^3
h=?
πrl=71.59
22/7×1.7×l=71.59
5.34l=71.59
l=71.59/5.34
l=13.4
h=?
l^2=r^2+h^2
13.4^2=1.7^2+h^2
179.56=2.89+h^2
h^2=179.56-2.89
h^2=176.67
h=√176.67
h=13.29
here is your answer hope it helps you enough
h=5.8
Csa if cone = πrl
l=?
l^2=r^2+h^2
l^2=3.4^2+5.8^2
l^2=11.56+33.64
l^2=45.2
l=√45.2
l=6.7
csa=πrl
=22/7×3.4×6.7
=71.59cm^3
radius of new cone formed=1.7cm
area =71.59^3
h=?
πrl=71.59
22/7×1.7×l=71.59
5.34l=71.59
l=71.59/5.34
l=13.4
h=?
l^2=r^2+h^2
13.4^2=1.7^2+h^2
179.56=2.89+h^2
h^2=179.56-2.89
h^2=176.67
h=√176.67
h=13.29
here is your answer hope it helps you enough
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