Question

pls solve this problem​

Answer 1

x + y = 4

on Cubeing both sides

(x+y) ^3 = (4) ^3

=>x^3 + y^3 + 3xy (x+y) =64

=> x^3 + y^3 + 3xy(4) = 64

=> x^3 + y^3 +12xy = 64

=>x^3 + y^3 +12xy - 64 = 0

=>x^3 + y^3 - 64 + 12xy = 0

Hence answer is o

Answer 2

hope it helps..........