Question

pls solve this problem​

Answer 1

Question:

In the given figure, ABCD is a parallelogram the measure of angle B is

Given:

ABCD is a parallelogram

$\angle A$ = 95°

To find: $\angle B$

Solution:

We know,

Opposite angles of parallelogram are equal.

So,

$\angle D = \angle B$ (Equation 1)

$\angle A = \angle C = 95^{\circ}$ (Equation 2)

$\angle A + \angle B + \angle C + \angle D = 360^{\circ}$ (Angle Sum Property of Quadrilateral) (Equation 3)

From Equation 1, Equation 2 and Equation 3

$\angle A + \angle B + \angle C + \angle D = 360^{\circ} \\ 95^{\circ} + \angle B + 95^{\circ} + \angle B = 360^{\circ} \\ 190^{\circ} + 2\angle B = 360^{\circ} \\ 2\angle B = 360^{\circ} - 190^{\circ} \\ \angle B = \dfrac{170^{\circ}}{2} \\ \angle B = 85^{\circ}$

Therefore, the measure of $\angle B$ is 85°.