Question

pls solve this ques urgently​

Answer 1

Step-by-step explanation:

(i) In ∆PSQ and ∆ PSR

PQ = PR ( given)

angle QPS = angle RPS

(ps is bisector of angleQPR)

PS = PS (common)

Therefore,

∆ PSQ congurent ∆ PSR

(ii) angle Q = angle R ( by cpct)

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