pls solve this question
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Step-by-step explanation:
-3 lies in (-inf ,0)
f(-3) = -3^2 -3 -5 =1
5 lies in (3, inf)
f(5) = 5^2 +3*5-2=38
2 not lies in any of range use last eqn
f(2)=2^2-3=1
-1 again lies in(-inf,o)
f(-1)=-1^2 -1 -5= -5
0 don't lie in any range use otherwise condition
f(0)=0^2-3= -3
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