Question

Pls solve this question.

Answer 1

Step-by-step explanation:

$\frac{ {sec}^{2}a \: - {cot}^{2}(90 - a) }{3( {sin}^{2}a + {sin}^{2}(90 - a))} - \: 4 {tan}^{2}30 {cos}^{2}53 {cosec}^{2}37 + \frac{3( {cosec}^{2}50 - {tan}^{2}40) }{2(sin48sec42)} \\ = \frac{ {sec}^{2}a \: - {tan}^{2}( a) }{3( {sin}^{2}a + {cos}^{2}(a))} - \: 4 ( { \frac{1}{ \sqrt{3} }) }^{2} {cos}^{2}53 {sec}^{2}53 + \frac{3( {cosec}^{2}50 - {cot}^{2}50) }{2(sin48cosec48)} \\ = \frac{1}{3(1)} - \frac{4}{3} \times 1 + \frac{3}{2} \\ = \frac{1}{3} - \frac{4}{3} + \frac{3}{2} \\ = - 1 + \frac{3}{2} \\ = \frac{1}{2}$