Question

pls solve this question

Answer 1

hey!
#ur solution:
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let one of the side be x and the other be x+5

by Pythagoras therom =>

$2 {5}^{2} = {x}^{2} + (x + 5 {)}^{2} \\ \\ 625 = {x}^{2} + {x}^{2} + 25 + 10x \\ \\ 2 {x}^{2} + 10x + 25 = 625 \\ \\ 2{x}^{2} + 10x - 600 = 0 \\ \\ {x}^{2} + 5x - 300 \\ \\ now \: factorise \\ \\ {x}^{2} + 20x - 15x - 300 = 0 \\ \\ x(x + 20) - 15(x + 20) = 0 \\ \\ (x - 15)(x + 20) = 0 \\ \\ x = 15 \\ x = - 20 \\ \\ x \: cannot \: be \: negative \\ so \\ \\ x = 15 \:( one \:s ide)\\ x + 5 = 20(second \: side)$

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