Question

pls solve this question

Answer 1

Answer:

0

Step-by-step explanation:

Given Equations are x^1/p = y^1/q = z^1/r and xyz = 1.

Let x^1/p = y^1/q = z^1/r = k.

(i)

x^1/p = k

x = k^p

(ii)

y^1/q = k

y = k^q

(iii)

z^1/r = k

z = k^r.

Given that xyz = 1

⇒ k^p * k^q * k^r = 1

⇒ k^(p + q + r) = k^0

⇒ p + q + r = 0.

Hope it helps!

Answer 2

Step-by-step explanation:

x^1/p = y^ 1/q

X = y^p/q

y ^ 1/q = z^1/r

y = z^q/r

X = z^( q/r x p/q)

X= z^ ( p/r)

XYZ = 1

z^p/r z^q/r z = 1

Z^ ( p/r + q/r +1) = 1

P/r + q/r + 1 =0

P+ q + r = 0