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Answered by
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Heya
_______________________________
Tan ( A + B ) = Tan ( 45° )
Becoz Tan ( 45° ) = 1
A + B = 45° ... equation ( i )
Tan ( A - B ) = Tan ( 30° )
Becoz Tan ( 30° ) = 1/√3
A - B = 30° ... equation ( ii )
ADDING BOTH THE EQUATIONS
2A = 75°
=>
A = 37.5°
Now, put value of A in Equation ( i )
B = 45° - 37.5°
B = 7.5°
So, The value of A = 37.5° And B = 7.5°
_______________________________
Tan ( A + B ) = Tan ( 45° )
Becoz Tan ( 45° ) = 1
A + B = 45° ... equation ( i )
Tan ( A - B ) = Tan ( 30° )
Becoz Tan ( 30° ) = 1/√3
A - B = 30° ... equation ( ii )
ADDING BOTH THE EQUATIONS
2A = 75°
=>
A = 37.5°
Now, put value of A in Equation ( i )
B = 45° - 37.5°
B = 7.5°
So, The value of A = 37.5° And B = 7.5°
thanku
but whether this is right
Absolutely right .... As u can cross check it as well by value of A And B in given question u will get L.H.S = R.H.S
*putting
thanku
Answered by
1
we know tan45=1
and tan (a+b) =1
so (a+b)=45... ...i
we know tan 30 =1/√3
so. tan (a-b) =30.....ii
from I and II
2a =75
a = 37.5
so b= 7.5 .
and tan (a+b) =1
so (a+b)=45... ...i
we know tan 30 =1/√3
so. tan (a-b) =30.....ii
from I and II
2a =75
a = 37.5
so b= 7.5 .
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