CBSE BOARD X, asked by Anonymous, 3 months ago

pls solve this question and send me the answers.Unnecessary answers will be reported​

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Answered by PurvaAnantwar
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Explanation:

Given,  tan θ = 12131213 …….. (1)  We know that by definition,  tan θ = Perpendicular side opposite to ∠θ / Base side adjacent to ∠θ …… (2)  On comparing equation (1) and (2), we have  Perpendicular side opposite to ∠θ = 12  Base side adjacent to ∠θ = 13  Thus, in the triangle representing ∠ θ we have,  Hypotenuse AC is the unknown and it can be found by using Pythagoras theorem  So by applying Pythagoras theorem, we have  AC2 = 122 + 132  AC2 = 144 + 169  AC2 = 313  ⇒ AC = √313  By definition,  sin θ = Perpendicular side opposite to ∠θ / Hypotenuse = ABACABAC  ⇒ sin θ = 12313√12313…..(3)  And, cos θ = Base side adjacent to ∠θ / Hypotenuse = BCACBCAC  ⇒ cos θ = 13313√13313 …..(4)  Now, substituting the value of sin θ and cos θ from equation (3) and (4) respectively in the equation below Therefore, 2sinθcosθcos2θ−sin2θ2sinθcosθcos2θ−sin2θ = 3122531225.Read more on Sarthaks.com - https://www.sarthaks.com/636755/if-tan-12-13-find-the-value-of-2sin-cos-cos-2-sin-2

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