Question

pls solve this question aryabhatta of maths plsss................................in dire need........ as fast as u can

Answer 1

Given : 2^a = 3^b = 6^c

Let 2^a = 3^b = 6^c = k

(i) 2^a = k

= > 2 = k^(1/a)  ------- (1)

(ii) 3^b = k

= > 3 = k^(1/b)   ------ (2)

(iii) 6^c = k

= > 6 = k^(1/c)   ----- (3)

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Now,

We know that 6 can be written as 3 * 2

= > 6 = 3 * 2

= > k^(1/c) = k^(1/a) * k^(1/b)

= > k^(1/c) = k^(1/a + 1/b)

= > k^(1/c) = k^(a + b/ab)

= > (1/c) = (a + b)/ab

= > c = ab/a + b.

Hope it helps!

Answer 2

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