Question

Pls solve this Question
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Answer 1

Given data :

1- Radius of the tube = 0.25 mm = 0.025 cm
2- Density of liquid = 13.6 g/cm³
3- Tension = 545 dyne/cm
4- Angle of contact = 120°
5- h = ?

$h = \frac{2T \cos( \alpha ) }{rg \times density}$
$h = \frac{2 \times 545 \cos(120) }{0.025 \times 9.8 \times 13.6}$
Solving these,
h = -163.56 can

So, Depression = 163.56 cm