Question

pls solve this question. The one who solve this question will get brainlist

Answer 1

AC = AB + BC
AC = AB + BO + OC
AC = AO + OC    ( BECAUSE AB + BO = AO )
AO = AC - OC
AND
SIMILARLY

BD = OD + BO
OD = BD - BO

NOW AO = OD RADIUS OF CIRCLE

SO AC - OC = BD -  BO
SO BY EQUALITY IN EXPONENTS WE HAVE 
 OC = BO

AS WE HAVE OC = BO
So OA = OD RADIUS
SO AB + OB = OC + CD
AS OB = OC 

We have  AB = CD

HENCE PROVED.