Pls solve this to.note that the end of the equ... there should be -3xyx (printing mistake)
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take x+y=x
y+z=y and
z+x=z
after that we get
L.H.S
= (x)^3+(y)^3+(z)^3-3xyz
= (x+y+z)(x^2+y^2+z^2-xy-yz-zx)
now ,put the value in place of x y and z and solve ... it will be equal as R.H.S
y+z=y and
z+x=z
after that we get
L.H.S
= (x)^3+(y)^3+(z)^3-3xyz
= (x+y+z)(x^2+y^2+z^2-xy-yz-zx)
now ,put the value in place of x y and z and solve ... it will be equal as R.H.S
Answered by
1
here is your prove of the answer hope it will help you and plz mark it as brainliest
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DebashishJoshi:
plz mark it as brainliest
its not showing that marked as brainliest
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