Question

Pls solve this two questions for me.. Physics​

Answer 1

Explanation:

for question (d)

Given:- force(F)= 20000dyne= 20N, displacement (s)= 80cm=0.8m, angle(theta)=60 degree

to find:- work done(W)=?

solution:-

W= Fscostheta

W=20×0.8×cos60

W= 20×0.8×1/2

W=10×0.8

W=8 joule

now for question (e)

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Answer 2

solution

e)

given

weight = 400N

K.E = 500j

g= m/s²

K.E

$as \: we \: know \: K.E = \frac{1}{2} m {v}^{2} - - - - (1)$

here we do not mave mass (m) of body

to find mass

$as \: we \: know \: weight \: = mg \\ \\ so \: 400 = m10 \: \: \: (coz \: g \: and \: weight \: are \: given \: ) \\ \\ then \: m = \frac{400}{10} \\ \\ m = 40kg$

Now by putting value in equation 1

$500 = \frac{1}{2} 40 {v}^{2} \: \: \: \: \: \: \: (ke \: mass \: \: are \: given \: ) \\ \\ 500 = 20 {v}^{2} \: \: \: \: (on \: dividing \: 40 \: by \: 2 \: we \: get \: 20) \\ \\ {v}^{2} = \frac{500}{20} \\ \\ {v}^{2} = 25 \: \: \: (coz \: 500 \div 20 = 25) \\ the \: squire \: will \: convert \\ in \: root \: in \: rhs \: side \: \\ \\ v = \sqrt{25} \\ \\ v = 5m {s}^{ - 1}$

therefore velocity of object having ke = 500j and weight of 400N is 5m/s¹

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