Math, asked by ojaswiverma97, 2 months ago

pls solve this using properties of ratio and proportion
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Answered by MysticSohamS
2

Answer:

hey here is your solution

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Step-by-step explanation:

to \: solve :  \\ for \: value \: of \: x \\  \\ given \: equation :  \\  \\  \frac{ \sqrt{a + x}  +  \sqrt{a - x} }{ \sqrt{a + x} -  \sqrt{a - x}  }  =  \frac{c}{d}  \\  \\ applying \: componendo \: dividendo \\  \\  \frac{ \sqrt{a + x}  +  \sqrt{a - x}  +  \sqrt{a + x}  -  \sqrt{a - x} }    { \sqrt{a + x} +  \sqrt{a - x}  - ( \sqrt{a + x}  -  \sqrt{a - x})  }  =  \frac{c + d}{c - d}  \\  \\   ∴ \: \frac{2. \sqrt{a + x} }{2. \sqrt{a - x} }  =   \frac{c + d}{c - d}  \\  \\   \frac{ \sqrt{a + x} }{ \sqrt{a  - x} }  =  \frac{c + d}{c - d}  \\  \\ squaring \: both \: sides \\ we \: get \\  \\  \\  =  \frac{a + x}{a - x}  =  \frac{(c + d) {}^{2} }{(c - d) {}^{2} }  \\  \\  =  \frac{c {}^{2}  + d {}^{2}  + 2cd}{c {}^{2}  + d {}^{2}  - 2cd}  \\  \\ again \: applying \\ componendo \: dividendo \\  \\  \frac{a + x + a - x}{a + x - (a - x)}  =  \frac{c {}^{2}  + d {}^{2}  + 2cd + c {}^{2}  + d {}^{2}  - 2cd}{c {}^{2}  + d {}^{2}  + 2cd - (c {}^{2}  + d {}^{2}  - 2cd)  }  \\  \\  ∴ \:   \frac{2a}{2x}  =  \frac{2c {}^{2} + 2d {}^{2}  }{2cd + 2cd}  \\  \\   ∴ \: \frac{a}{x}  =  \frac{2(c {}^{2} + d {}^{2} ) }{4cd}  \\  \\  =  \frac{a}{x}  =  \frac{c {}^{2}  + d {}^{2} }{2cd}  \\  \\  \\ ∴(c {}^{2}  + d {}^{2} )x = 2acd \\  \\ x =  \frac{2acd}{c {}^{2} + d {}^{2}  }

Answered by aritradas79
1

Answer:

what is genotype ?

answer

The genotype of an organism is its complete set of genetic material. However, the term is often used to refer to a single gene or set of genes, such as the genotype for eye color. The genes partly determine the observable characteristics of an organism, such as hair color, height, etc

Step-by-step explanation:

What is VIBGYOR?

answer

VIBGYOR (Violet–Indigo–Blue–Green–Yellow–Orange–Red) is a popular mnemonic device used for memorizing the traditional optical spectrum.

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