Math, asked by Elohim, 10 months ago

pls solve this using ( x+y)^3 = x^3+y^3 + 3x^2y+3xy^2​

Attachments:

Answers

Answered by nisha0410
1

Answer:

 {x}^{3}  +  {y}^{3}  = (x + y)( {x}^{2}  - xy +  {y}^{2}) \\

solving rhs

 = x( {x}^{2}  - xy +  {y}^{2} ) + y( {x}^{2}  - xy +  {y}^{2} ) \\ =   {x}^{3}  -  {x}^{2}y +  x {y}^{2}  +  {x}^{2}y - x {y}^{2}  +  {y}^{3}  \\  =  {x}^{3} +  {y}^{3}

hence proved

hope it helps you

Similar questions