Question

pls solve value of x and y​

Answer 1

Answer:

x=2,y=1

Step-by-step explanation:

(x + iy)^2 = 3 + 4i

x^2 + 2xiy + i^2Y^2 =3 + 4i

x^2 + 2xiy + (-1)y^2 = 3 + 4i

x^2 + 2xiy -y^2 = 3 + 4i

COMPARIND BOTH SIDES:

x^2 - y^2 = 3

2xy = 4

Xy = 2

y = x/2

x^2 - (x/2)^2 = 3

x^2(1-1/4) = 3

x^2(3/4) = 3

x = 2

y = x/2

y = 1

therefore,x=2 , y=1.