Math, asked by khushi86023, 1 year ago

pls somebody solve this question....

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Answered by Anonymous
3

We know that

  • 1 + tan²A = sec² A

   ⇒ 1 = sec² A - tan² A

  ⇒ 1 = (sec A + tan A ) ( sec A - tan A)

∴   sec A + tan A = 1/(sec A - tan A )................(i)

  • 1 + cot² A = cosec² A

  ⇒ 1 =  cosec² A - cot² A

  ⇒ 1 = (cosec A + cot A )(cosec A - cot A)

∴   cosec A + cot A = 1/(cosec A - cot A ).................(ii)


→ By putting the (i) and (ii). on L.H.S we get R.H.S.


khushi86023: thanks
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