Question

Pls someone answer this also pls...

Answer 1

if x^2 +5px +16 has no real roots

then discriminant<0

b^2 - 4 ac <0 in ax^2 + bx + c

So

Compare

(5p)^2 - 4(1)(16)<0

25 p^2 <64

p^2<64/25

p<8/5, p>-8/5

So -8/5<p<8/5

Answer 2

Answer:

Option(B)

Step-by-step explanation:

Given Equation is x² + 5px + 16.

Here, a = 1, b = 5p, c = 16.

The equation has no real roots.

∴ D < 0

b² - 4ac < 0

⇒ (5p)² - 4(1)(16) < 0

⇒ 25p² - 64 < 0

⇒ p² < 64/25

⇒ p < ±8/5.

Therefore, the solution is -8/5 < p < 8/5.

Hope it helps!