Question

pls someone
give the answer for this . as soon as possible

Answer 1

Answer:

For x>-1 it is strictly decreasing and for x<-1 it is strictly increasing. Note that x cannot be -1 or less than -1 as logarithm of non-positive integers is not defined. So the final answer will be f(x) is strictly decreasing and in the interval  (-1,∞] i.e, -1 to infinity and -1 not included in case you don't know sets.

Step-by-step explanation:

Differentiate the function with respect to x. You will get f'(x) as -3/(1+x). Put the inequalities f'(x)<0 and f'(x)>0 to get intervals for increasing and decreasing functions. But f(x)>0 won't be valid( see the reason above in the answer).

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