pls someone
give the answer for this . as soon as possible
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For x>-1 it is strictly decreasing and for x<-1 it is strictly increasing. Note that x cannot be -1 or less than -1 as logarithm of non-positive integers is not defined. So the final answer will be f(x) is strictly decreasing and in the interval (-1,∞] i.e, -1 to infinity and -1 not included in case you don't know sets.
Step-by-step explanation:
Differentiate the function with respect to x. You will get f'(x) as -3/(1+x). Put the inequalities f'(x)<0 and f'(x)>0 to get intervals for increasing and decreasing functions. But f(x)>0 won't be valid( see the reason above in the answer).
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Ankitaaaaa:
how is f'(x)=-3/x+1
i am getting it as x(x+4)/(x+1)(x+2)^2
The function will be log(1+x)-3+.....
take the coefficients inside and differentiate properly(yeah properly) Do you know chain rule and product rule?
Please do ask if you have any doubt
Yeah and if you are satisfied pleaae mark the answer brainliest
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