pls tell answer please both
Attachments:
Answers
Answered by
0
Step-by-step explanation:
1) Let numbers be a and b.
Given : a- b = 5
and a²-b²=300
Using identity a²-b² = (a+b)(a-b)
(a+b)(5) = 300
So, (a+b) = 60.
2) rootx + 1/rootx = y ..... (Assume)
Squaring both sides,
x + 1/x + 2 = y²
2 + 2 = y² ....(Given x+1/x =2)
y = root4 = 2
Answered by
0
Step-by-step explanation:
let x and y be numbers
x-y=5
x=5+y.............1eq
x²-y²=300
(5+y)²
5²+y²+2×5×y
25+y²+25y
y²+25y+25
now we will factrorise by middle term splitting
y²+25y+1y+25
y(y+25)+1(y+25)
y+1. and. y+25
y=-1. y=-25
we will take y=-25
and put it in 1eq
x=5-25
x=-20
sum of x and y is
-20+(-25)
-20-25
-45 is ans
Similar questions