Math, asked by ankitnandal840, 7 months ago

pls tell answer please both​

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Answered by AdityaPhadnis
0

Step-by-step explanation:

1) Let numbers be a and b.

Given : a- b = 5

and a²-b²=300

Using identity a²-b² = (a+b)(a-b)

(a+b)(5) = 300

So, (a+b) = 60.

2) rootx + 1/rootx = y ..... (Assume)

Squaring both sides,

x + 1/x + 2 = y²

2 + 2 = y² ....(Given x+1/x =2)

y = root4 = 2

Answered by rakshit9847
0

Step-by-step explanation:

let x and y be numbers

x-y=5

x=5+y.............1eq

x²-y²=300

(5+y)²

5²+y²+2×5×y

25+y²+25y

y²+25y+25

now we will factrorise by middle term splitting

y²+25y+1y+25

y(y+25)+1(y+25)

y+1. and. y+25

y=-1. y=-25

we will take y=-25

and put it in 1eq

x=5-25

x=-20

sum of x and y is

-20+(-25)

-20-25

-45 is ans

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