pls tell me how to solve
lV
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In this pic your answers
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aayush50:
bro 2nd pic me 1st step kese keya.!
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x^3 + x^2 - 4x^2 - 4x - 5x - 5
= x^2 ( x + 1) - 4x ( x + 1) - 5 ( x + 1 )
=(x+1) ( x^2 -4x - 5 )
= (x+1) ( x^2 - 5x + x - 5)
= (x+1) [x(x-5) + 1 ( x-5)]
= (x+1)(x+1)(x-5)
= x^2 ( x + 1) - 4x ( x + 1) - 5 ( x + 1 )
=(x+1) ( x^2 -4x - 5 )
= (x+1) ( x^2 - 5x + x - 5)
= (x+1) [x(x-5) + 1 ( x-5)]
= (x+1)(x+1)(x-5)
1st step kese keya!?
Main equation ko split karke..first equation me x ki jagah 1 ya -1 k values daal kr check kro..-1 dalne pr equation 0 hta h..so x= -1 ya x+1 is a root
1^3 - 3(-1)^2 - 9 (-1) - 5 = 0
bro, vo tune no... nekalne ke lea keska multiply kara he.!!?
Konsa number? Equation ko bas aise todna h ki koi common factor ban jaye jaise (x+1)
x^3 -3x^2 -9x - 5
=x^3 +(x^2 - 4x^2) - (4x + 5x) - 5
isme x^2 - 4x^2= -3x^2 and 4x + 5x = 9x
=x^3 +(x^2 - 4x^2) - (4x + 5x) - 5
isme x^2 - 4x^2= -3x^2 and 4x + 5x = 9x
x²-4x² ye no.. kase pata chala
bas numbr ko todna h taki common factor bana sake
(x+1) multiple kiya (x+1) se
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