Question

pls tell right ans..​

Answer 1

Answer:

force h 5 sec of fir agaya to the aditor of English University admission

Answer 2

Explanation:

☛Force, F=10N

Mass, m=5Kg

Force,

F=ma

a=2m/s/2

Work done, W=F.ds

In first second, displacement,

$\\ =21at2</p><p></p><p> \\ s=21×2×1</p><p></p><p> \\ s=1m</p><p></p><p>$

So, work done,W=10×1=10J

In second second, s= 2/1 ×2×4=4m

So, the displacement is , 4−1=3m

Hence, work done in 2 second is,

W=10×3

W=30J

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