Question

Pls tell the answer

Answer 1

In triangle APD,

AP = PD

Since angle opposite to equal sides are equal

Let ∠APD = ∠ADP = x ..............1

Again, sum of interior angles of a triangle are 180

Now, ∠PAD = 180 - 2x ............2

Again in triangle BPC,

BP = PC

Let ∠BPC = ∠PCB = Y ..............3

AND ∠PBC = 180 - 2y ............4

Since the sum of the adjacent angles are 180

So, ∠PAD + ∠PBC = 180

Add equation 2 and 4, we get

180 - 2x + 180 - 2y = 180

=> 360 - 2x - 2y = 180

=> 360 - 180 = 2x + 2y

=> 2x + 2y = 180

=> x + y = 90 ............5

Now, ∠CPD = 180 - (x + y)

=> ∠CPD = 180 - 90

=> ∠CPD = 90

hope it's help you....

Answer 2

answer of the question will be (A)