Question

pls tell the answer​

Answer 1

i) (a+2b)^2

(3)^2 = a^2 + 4b^2 + 4ab

9 = a^2 + 4b^2 + 4 (-5)

9+20 = a^2 + 4b^2

a^2 + 4b^2 =29

ii) (a+2b)^3 = a^3 + 8b^3 + 6a^2b + 12ab^2

(3)^3 = a^3 + 8b^3 + 6ab (a+2b)

27= a^3 + 8b^3 + 6 (-5) (3)

27 + 90 = a^3 + 8b^3

a^3 + 8b^3 = 117

Hope it helped u!