pls tell the answer of question 12,13 and 14
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(1) In triangle DAB and CBA ,we have,
AD=BC (given)
Angle DAB = angle CBA (given)
BA = BA (common)
Therefore, triangle DAB is congruent to triangleCBA by SAS congruence ...(i)
By CPCT,BD =AC
(2) Subtracting triangle AOB from equation (i),we get,
TRIANGLE DOA is congruent to triangle COB
NOW,BY CPCT, DO =CO
Proved
AD=BC (given)
Angle DAB = angle CBA (given)
BA = BA (common)
Therefore, triangle DAB is congruent to triangleCBA by SAS congruence ...(i)
By CPCT,BD =AC
(2) Subtracting triangle AOB from equation (i),we get,
TRIANGLE DOA is congruent to triangle COB
NOW,BY CPCT, DO =CO
Proved
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